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It takes 30 cm³ of 1.0 mol dm-3 hydrochloric acid to neutralise 24 cm³ of potassium hydroxide (koh) solution. what is the concentration of the potassium hydroxide solution?)
Accepted Answer
The concentration of the potassium hydroxide solution is 1.25 mol dm-3. Here's how to calculate it:
1. Write the balanced chemical equation:
HCl(aq) + KOH(aq) → KCl(aq) + H₂O(l)
2. Determine the moles of HCl:
Moles of HCl = Concentration × Volume
Moles of HCl = (1.0 mol dm-3) × (30 cm³ / 1000 cm³/dm³) = 0.03 mol
3. Use the mole ratio from the balanced equation:
The mole ratio of HCl to KOH is 1:1. Therefore, 0.03 mol of HCl reacts with 0.03 mol of KOH.
4. Calculate the concentration of KOH:
Concentration of KOH = Moles of KOH / Volume of KOH
Concentration of KOH = 0.03 mol / (24 cm³ / 1000 cm³/dm³) = 1.25 mol dm-3
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