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Liquid hexane reacts with gaseous oxygen gas to produce gaseous carbon dioxide and gaseous water . if 13.4 of water is produced from the reaction of 34.5 g of hexane and 55.9 g of oxygen gas, calculate the percent yield of water. round your answer to 3 significant figures. What is the answer?
Accepted Answer
The percent yield of water is 76.2%. Here's how to calculate it:
1. Write the balanced chemical equation:
C6H14(l) + 19/2 O2(g) → 6 CO2(g) + 7 H2O(g)
2. Calculate the theoretical yield of water:
- Convert grams of hexane to moles: 34.5 g C6H14
(1 mol C6H14 / 86.18 g C6H14) = 0.400 mol C6H14
- Use the mole ratio from the balanced equation to find moles of water: 0.400 mol C6H14
(7 mol H2O / 1 mol C6H14) = 2.80 mol H2O
- Convert moles of water to grams: 2.80 mol H2O
(18.02 g H2O / 1 mol H2O) = 50.5 g H2O
3. Calculate the percent yield:
- Percent Yield = (Actual Yield / Theoretical Yield)
100%
- Percent Yield = (13.4 g H2O / 50.5 g H2O)
100% = 76.2%
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