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Maximum multiplicity was found in a transition metal ion of d2 configuration. the term symbol would be
Accepted Answer
The term symbol for a d2 configuration with maximum multiplicity is ³F. Here's why:
1. Multiplicity: For a d2 configuration, there are two unpaired electrons. The multiplicity is calculated as 2S + 1, where S is the total spin angular momentum. With two unpaired electrons, S = 1, resulting in a multiplicity of 3 (triplet state).
2. Total Orbital Angular Momentum (L): The d orbitals have l = 2. For two electrons, the possible values of L range from 0 (when the spins are anti-parallel) to 4 (when the spins are parallel). The maximum value of L for a d2 configuration is 4, corresponding to the F term symbol.
3. Term Symbol: The term symbol is written as 2S+1LJ, where J is the total angular momentum (L+S) and ranges from L-S to L+S. In this case, L=4, S=1, and J can be 3, 4, or 5. However, the maximum multiplicity (³F) corresponds to the term symbol ³F with J=3.
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