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Mechanism of propyne to form a carboxylic acid and carbon iv oxide reagents are KMnO4 or o3
Accepted Answer
The reaction of propyne (CH3C≡CH) with either KMnO4 (potassium permanganate) or O3 (ozone) will produce a carboxylic acid and carbon dioxide. Here's a breakdown:
With KMnO4:
Oxidation: KMnO4 is a strong oxidizing agent. It will cleave the triple bond in propyne, oxidizing the carbons to form a carboxylic acid. The carbon at the original triple bond will be oxidized to carbon dioxide.
Reaction: CH3C≡CH + 4[O] → CH3COOH + CO2 + H2O
With O3:
Ozonolysis: Ozone (O3) reacts with the triple bond, cleaving it and forming ozonides. These ozonides are then hydrolyzed to form a carboxylic acid and carbon dioxide.
Reaction: CH3C≡CH + 2O3 → CH3COOH + CO2 + H2O
In both cases, the final product will be ethanoic acid (acetic acid) and carbon dioxide.
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