Frequently Asked Question

Questions asked by users might not always be phrased in the clearest way.

Na3[V(CN)6] d configuration

Accepted Answer

The d-configuration of vanadium in Na3[V(CN)6] is d².
Here's why:
1. Vanadium's Electronic Configuration: Vanadium (V) has an atomic number of 23, so its ground state electronic configuration is [Ar] 3d³ 4s².
2. Oxidation State: In Na3[V(CN)6], vanadium is in the +3 oxidation state. This means it loses three electrons.
3. CN- Ligand: The cyanide ion (CN-) is a strong field ligand, meaning it causes a large splitting of the d orbitals.
4. d-Configuration: Removing three electrons from the neutral vanadium atom, and considering the strong field nature of CN-, the d-configuration of V³⁺ in this complex is d² (two electrons in the lower energy d orbitals).


Articles you might like

Discover more articles
🚀 Welcome to TheAiWay! ChemistAI has evolved into TheAiWay.org, offering faster speeds, expanded AI-powered content across 32 subjects, and a brand-new, user-friendly design. Enjoy enhanced stability, increased query limits (30 to 100), and even unlimited features! Discover TheAiWay.org today! ×