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Na3[V(CN)6] oxidation state
Accepted Answer
In the complex ion [V(CN)6]3-, the oxidation state of vanadium (V) is +3. Here's how to determine it:
Cyanide (CN-) has a charge of -1.
Six cyanide ions contribute a total charge of -6.
The overall complex ion has a charge of -3.
Therefore, the oxidation state of vanadium must be +3 to balance the charges: +3 + (-6) = -3.
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