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Number of oxygen atoms in 35 g magnesium nitrate with calculation
Accepted Answer
Calculation:
1. Convert the mass of magnesium nitrate to moles:
moles Mg(NO3)2 = 35 g / (24.31 g/mol + 2*(14.01 g/mol) + 6*(16.00 g/mol))
= 0.242 mol
2. Determine the number of moles of oxygen in 1 mole of magnesium nitrate:
moles O in 1 mole Mg(NO3)2 = 6 moles
3. Multiply the moles of magnesium nitrate by the number of moles of oxygen per mole of magnesium nitrate to get the total moles of oxygen:
moles O = 0.242 mol Mg(NO3)2 * 6 moles O / 1 mole Mg(NO3)2
= 1.452 moles O
4. Convert the moles of oxygen to the number of atoms:
Number of O atoms = 1.452 moles O * (6.022 x 10^23 atoms/mol)
= 8.73 x 10^23 atoms
1. Convert the mass of magnesium nitrate to moles:
moles Mg(NO3)2 = 35 g / (24.31 g/mol + 2*(14.01 g/mol) + 6*(16.00 g/mol))
= 0.242 mol
2. Determine the number of moles of oxygen in 1 mole of magnesium nitrate:
moles O in 1 mole Mg(NO3)2 = 6 moles
3. Multiply the moles of magnesium nitrate by the number of moles of oxygen per mole of magnesium nitrate to get the total moles of oxygen:
moles O = 0.242 mol Mg(NO3)2 * 6 moles O / 1 mole Mg(NO3)2
= 1.452 moles O
4. Convert the moles of oxygen to the number of atoms:
Number of O atoms = 1.452 moles O * (6.022 x 10^23 atoms/mol)
= 8.73 x 10^23 atoms
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