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Oxalic acid + potassium dichromate form potassium dioxalato-diaquachromate (iii)

Accepted Answer

The reaction between oxalic acid (H₂C₂O₄) and potassium dichromate (K₂Cr₂O₇) in acidic conditions produces potassium dioxalatodiaquachromate(III) ([Cr(C₂O₄)₂(H₂O)₂]⁻), carbon dioxide (CO₂), and water (H₂O). The reaction involves the reduction of dichromate ions (Cr₂O₇²⁻) to chromium(III) ions (Cr³⁺) and the oxidation of oxalic acid to carbon dioxide. Here's the balanced equation:
K₂Cr₂O₇ + 3 H₂C₂O₄ + 7 H₂SO₄ → 2 [Cr(C₂O₄)₂(H₂O)₂]⁻ + 6 CO₂ + 7 H₂O + K₂SO₄ + 5 H₂SO₄


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