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Percent composition of tin (iv) phosphate

Accepted Answer

To calculate the percent composition of tin (IV) phosphate (Sn3(PO4)4), we need to follow these steps:
1. Determine the molar mass of the compound:

Sn: 118.71 g/mol
3 = 356.13 g/mol

P: 30.97 g/mol
4 = 123.88 g/mol

O: 16.00 g/mol
16 = 256.00 g/mol

Total molar mass: 356.13 + 123.88 + 256.00 = 736.01 g/mol
2. Calculate the percentage of each element:

% Sn: (356.13 g/mol / 736.01 g/mol)
100% = 48.37%

% P: (123.88 g/mol / 736.01 g/mol)
100% = 16.84%

% O: (256.00 g/mol / 736.01 g/mol)
100% = 34.80%
Therefore, the percent composition of tin (IV) phosphate is:

Tin (Sn): 48.37%
Phosphorus (P): 16.84%
Oxygen (O): 34.80%

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