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Place these free ion term symbols 1d ,3f ,3p and 1s in order of decreasing energy
Accepted Answer
The order of decreasing energy for the free ion term symbols is: 3F > 3P > 1D > 1S. This follows Hund's rules, which state that:
1. Higher multiplicity (spin) has higher energy: 3F and 3P have a higher spin multiplicity than 1D and 1S, placing them higher in energy.
2. Higher L value has higher energy: 3F has a higher L value (L = 3) than 3P (L = 1), making it higher in energy.
3. For the same L and S, higher J has higher energy: This is not relevant in this case since J is not specified for each term symbol.
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