Top topic this week
Back to FAQs
Related FAQs
Frequently Asked Question
Questions asked by users might not always be phrased in the clearest way.
Scientists discover a 40.8 gram chunk of a new radioisotope buried in a meteorite. Preliminary analysis reveals it has a half-life of 19.5 hours. rnrnhow many grams of the radioisotope would remain after 5.00 days?
Accepted Answer
The amount of a radioisotope remaining after a certain amount of time can be calculated using the following equation:
Amt remaining = Initial Amt * (1/2)^(time/half-life)
where:
- Amt remaining is the amount of the radioisotope remaining after the given time
- Initial Amt is the initial amount of the radioisotope
- time is the amount of time that has passed
- half-life is the amount of time it takes for half of the radioisotope to decay
In this case, the initial amount of the radioisotope is 40.8 grams, the half-life is 19.5 hours, and the time that has passed is 5.00 days, which is equal to 120 hours.
Plugging these values into the equation, we get:
Amt remaining = 40.8 g * (1/2)^(120 h / 19.5 h)
Amt remaining = 40.8 g * (1/2)^6.15
Amt remaining = 40.8 g * 0.042
Amt remaining = 1.71 g
Therefore, after 5.00 days, there would be 1.71 grams of the radioisotope remaining.
Articles you might like