Top topic this week
Questions asked by users might not always be phrased in the clearest way.
The reaction of potassium dichromate (K2Cr2O7) and iron(II) chloride (FeCl2) is a redox reaction. Here's a breakdown of the balanced ionic equation and the steps involved:
1. Identify the reactants and products:
Reactants: K2Cr2O7 (aq) and FeCl2 (aq)
Products: CrCl3 (aq), FeCl3 (aq), KCl (aq), and H2O (l)
2. Write the unbalanced ionic equation:
Cr2O7^2- (aq) + Fe^2+ (aq) → Cr^3+ (aq) + Fe^3+ (aq)
3. Balance the half-reactions:
Oxidation half-reaction:
Fe^2+ (aq) → Fe^3+ (aq) + e^-
Reduction half-reaction:
Cr2O7^2- (aq) + 14H+ (aq) + 6e^- → 2Cr^3+ (aq) + 7H2O (l)
4. Multiply the half-reactions to balance electrons:
Oxidation half-reaction (multiply by 6):
6Fe^2+ (aq) → 6Fe^3+ (aq) + 6e^-
Reduction half-reaction (as is):
Cr2O7^2- (aq) + 14H+ (aq) + 6e^- → 2Cr^3+ (aq) + 7H2O (l)
5. Add the half-reactions together and cancel out common terms:
Cr2O7^2- (aq) + 14H+ (aq) + 6Fe^2+ (aq) → 2Cr^3+ (aq) + 7H2O (l) + 6Fe^3+ (aq)
6. Include spectator ions:
K2Cr2O7 (aq) + 14HCl (aq) + 6FeCl2 (aq) → 2CrCl3 (aq) + 7H2O (l) + 6FeCl3 (aq) + 2KCl (aq)
Note: The reaction is carried out in acidic conditions, hence the use of HCl. The potassium ions (K+) and chloride ions (Cl-) are spectator ions, meaning they do not participate in the reaction.