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So what is the ph for 5m CH3SO3H

Accepted Answer

The pH of a 5M solution of CH3SO3H can be calculated using the Henderson-Hasselbalch equation: pH = pKa + log([A-]/[HA]), where pKa is the dissociation constant of the acid, and [A-] and [HA] are the concentrations of the conjugate base and acid, respectively. For CH3SO3H, the pKa is 1.45. Substituting the given concentration (5M) into the equation, we get: pH = 1.45 + log([CH3SO3-]/[CH3SO3H]) = 1.45 + log(1) = 1.45. Therefore, the pH of a 5M solution of CH3SO3H is 1.45.

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