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Sodium borohydride reduction of benzil balanced equation

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The balanced equation for the sodium borohydride reduction of benzil is:
2 C14H10O2 + NaBH4 + 4 H2O → 2 C14H12O2 + NaBO2 + 4 H2
Benzil (C14H10O2) is reduced to hydrobenzoin (C14H12O2) by sodium borohydride (NaBH4) in the presence of water. This reaction is a classic example of a hydride reduction, where the hydride ion (H-) from sodium borohydride attacks the carbonyl group of benzil.

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