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The manganese(2) ion is known to have a d5 configuration having the following term symbols: 4g,4d,4f,6s,4p. The term symbol of highest energy would be ?
Accepted Answer
The term symbol of highest energy would be 6S.
Here's why:
Hund's Rules: These rules dictate the order of energy levels in atomic orbitals. The term symbol with the highest spin multiplicity (highest value of 'S') will have the highest energy.
Spin Multiplicity: The spin multiplicity (2S+1) for the 6S term symbol is 2(0) + 1 = 1, indicating a singlet state. This is the highest spin multiplicity among the given term symbols.
Other Factors: While Hund's rules are the primary factor, the 'L' value (representing total orbital angular momentum) can also influence energy. However, in this case, the difference in 'L' values between the terms symbols is not significant enough to override the spin multiplicity effect.
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