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The number of sulphur atoms in 3.20g of SO2 is .........…if O=16, S=32 avogadros constant is 6.02*10^23

Accepted Answer
Here's the number of sulphur atoms in 3.20g of SO2.

1. Calculate the number of moles of SO2 present in 3.20g using its molar mass (32 g/mol for S and 16 g/mol for each O atom, giving a total of 64 g/mol for SO2):
Number of moles of SO2 = 3.20 g / 64 g/mol = 0.05 mol
2. Determine the number of molecules in 0.05 mol of SO2 using Avogadro's constant (6.02 x 10^23 molecules/mol):
Number of molecules = 0.05 mol * 6.02 x 10^23 molecules/mol = 3.01 x 10^22 molecules
3. Since each SO2 molecule contains one sulfur atom, the number of sulfur atoms in 3.01 x 10^22 molecules of SO2 is:
Number of sulfur atoms = 3.01 x 10^22 molecules
Therefore, there are 3.01 x 10^22 sulfur atoms in 3.20g of SO2.

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