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The ph of a solution of HCl in water is found to be 2.50. What volume of water would you add to 1.00 l of this solution tornraise the ph to 3.10?
Accepted Answer
To raise the pH of a solution, we need to decrease the concentration of H+ ions. We can do this by adding a base, such as water, to the solution.
The pH of a solution is given by the following equation:
pH = -log[H+]
where [H+] is the concentration of hydrogen ions in moles per liter.
We can use this equation to calculate the concentration of H+ ions in the original solution:
[H+] = 10^-pH = 10^-2.50 = 3.16 x 10^-3 M
To raise the pH to 3.10, we need to decrease the concentration of H+ ions to:
[H+] = 10^-pH = 10^-3.10 = 7.94 x 10^-4 M
We can use the following equation to calculate the volume of water that we need to add to the original solution:
V1[H+]1 = V2[H+]2
where V1 is the original volume of the solution, [H+]1 is the original concentration of H+ ions, V2 is the new volume of the solution, and [H+]2 is the new concentration of H+ ions.
Solving for V2, we get:
V2 = V1[H+]1/[H+]2
Substituting in the values that we know, we get:
V2 = 1.00 L * (3.16 x 10^-3 M) / (7.94 x 10^-4 M) = 3.98 L
Therefore, we need to add 3.98 L of water to 1.00 L of the original solution to raise the pH to 3.10.
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