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The rate constant of a first order reaction is 3.46×10^-2s-1 at 298kwhat is the rate constant at 350k if the activation energy of the reaction is 50.2 kj/mol/assignment

Accepted Answer

The Arrhenius equation can be used to calculate the rate constant at a different temperature:

k = Ae^(-Ea/RT)

where:

* k is the rate constant
* A is the pre-exponential factor
* Ea is the activation energy
* R is the gas constant (8.314 J/mol*K)
* T is the temperature in Kelvin

We can rearrange this equation to solve for the pre-exponential factor:

A = ke^(Ea/RT)

We are given the rate constant at 298 K and the activation energy, so we can plug these values into the equation to solve for A:

A = (3.46 x 10^-2 s^-1) * e^[(50.2 kJ/mol) / (8.314 J/mol*K * 298 K)]

A = 1.23 x 10^11 s^-1

Now that we have the pre-exponential factor, we can use the Arrhenius equation again to calculate the rate constant at 350 K:

k = Ae^(-Ea/RT)

k = (1.23 x 10^11 s^-1) * e^[(50.2 kJ/mol) / (8.314 J/mol*K * 350 K)]

k = 0.212 s^-1

Therefore, the rate constant at 350 K is 0.212 s^-1.


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