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The volume of a gas with a pressure of 1.2 atm increases from 1.0 l to 4.0 l. What is the final pressure of the gas, assuming constant temperature?
Accepted Answer
This problem can be solved using Boyle's Law, which states that the product of pressure and volume is constant for a given mass of gas at a constant temperature. Mathematically, P₁V₁ = P₂V₂.
Here's how to solve it:
P₁ = 1.2 atm (initial pressure)
V₁ = 1.0 L (initial volume)
V₂ = 4.0 L (final volume)
P₂ = ? (final pressure)
Substituting the values into Boyle's Law equation:
(1.2 atm)(1.0 L) = P₂(4.0 L)
P₂ = (1.2 atm
1.0 L) / 4.0 L = 0.3 atm
Therefore, the final pressure of the gas is 0.3 atm.
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