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There is a purple power with a formula of [co(ox)3]4-. What is the ground state energy term?
Accepted Answer
The ground state energy term for [Co(ox)3]4- can be determined by applying the following steps:
1. Determine the electronic configuration of Co3+: Co is in the 9th group, so Co3+ has 3d6 configuration.
2. Consider the crystal field splitting: The oxalate ligand (ox) is a strong field ligand, resulting in a large splitting of the d orbitals. The six electrons will fill the lower energy t2g orbitals, giving a t2g6 eg0 configuration.
3. Apply Hund's rule: All electrons in the t2g orbitals are spin-paired, resulting in a total spin quantum number S = 0.
4. Determine the total orbital angular momentum: Since all t2g orbitals are filled, L = 0.
5. Calculate the term symbol: Using the formula 2S+1LJ, we get 1S0.
Therefore, the ground state energy term for [Co(ox)3]4- is 1S0.
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