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Two additional bands of weak intensity are usually found in the visible spectrum of [ni(nh3)6]2+ at 540nm and 650nm. Use the Tanabe-Sugano diagram (enclosed) to explain why this occurs.
Accepted Answer
The two weak bands at 540 nm and 650 nm in the visible spectrum of [Ni(NH3)6]2+ correspond to spin-forbidden transitions. The Tanabe-Sugano diagram for a d8 ion like Ni2+ shows that the ground state is 3A2g, while the excited states responsible for these weak bands are 1Eg and 1T2g. These excited states are spin-forbidden because they have a different spin multiplicity than the ground state (3A2g is a triplet, while 1Eg and 1T2g are singlets). Spin-forbidden transitions are less likely to occur than spin-allowed transitions, resulting in weaker absorption bands.
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