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Una disolución acuosa de Ca(OH)2 tiene una concentración de 6% en masa. Sabiendo que si densidad es de 1,050g/cm^3,calcula la molaridad ,la molalidad y la fracción molar del soluto.(hazlo sin hablar mucho)
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## Calculations:
1. Molarity (M):
Assume 100 g of solution.
Mass of Ca(OH)2 = 6 g
Moles of Ca(OH)2 = 6 g / 74.09 g/mol = 0.081 mol
Volume of solution = 100 g / 1.050 g/cm³ = 95.24 cm³ = 0.09524 L
Molarity = 0.081 mol / 0.09524 L = 0.85 M
2. Molality (m):
Mass of solvent (water) = 100 g - 6 g = 94 g = 0.094 kg
Molality = 0.081 mol / 0.094 kg = 0.86 m
3. Mole Fraction (X):
Moles of water = 94 g / 18.02 g/mol = 5.21 mol
Total moles = 5.21 mol + 0.081 mol = 5.29 mol
Mole fraction of Ca(OH)2 = 0.081 mol / 5.29 mol = 0.015
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