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What are the term free ions in order of decreasing energy 1d, 3f , 3p, 1s
Accepted Answer
The order of decreasing energy for the given terms is: 3F, 3P, 1D, 1S.
This is determined by the following rules:
n (principal quantum number): Higher n values correspond to higher energy levels. In this case, the 3s and 3p orbitals are at a higher energy level than the 1s orbital.
l (azimuthal quantum number): Higher l values within the same n value correspond to higher energy levels. For example, the 3F orbital has a higher energy than the 3P orbital, and the 3P orbital has a higher energy than the 3D orbital.
Please note that these rules are generalizations and there may be exceptions, particularly when considering interactions between orbitals and the number of electrons present.
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