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What can be formed when bromocyclopentane reacts with methanamine CH3-NH2?
Accepted Answer
Bromocyclopentane reacts with methanamine (CH3-NH2) to form N-methylcyclopentylamine and hydrogen bromide (HBr). The reaction is an example of a nucleophilic substitution reaction, where the methanamine nucleophile attacks the electrophilic carbon of the bromocyclopentane, resulting in the formation of a new bond between the nitrogen atom of the methanamine and the carbon atom of the bromocyclopentane. The bromide ion from the bromocyclopentane is released as a leaving group.
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