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What happens when (2r)-2-bromobutane reacts with CH3ONa and CH3OH at room temperature?
Accepted Answer
When (2R)-2-Bromobutane reacts with CH3ONa and CH3OH at room temperature, it undergoes a nucleophilic substitution reaction, resulting in the formation of (2R)-2-methoxybutane as the major product. This reaction proceeds via an SN2 mechanism, where the nucleophile (CH3O-) attacks the electrophilic carbon atom of the alkyl halide, displacing the leaving group (Br-) and inverting the stereochemistry at the reaction center.
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