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What is he entrophy chan under isothermal conditions (310k) at 1 atm of I2=>I(g)+I(g)
Accepted Answer
The entropy change under isothermal conditions (310 K) at 1 atm for the reaction I2(s) → 2I(g) can be calculated using the following steps:
1. Determine the standard entropy change (ΔS°) for the reaction. This can be found in standard thermodynamic tables or calculated using the standard entropies of the reactants and products.
2. Calculate the entropy change at the given temperature and pressure. Since the reaction is isothermal, we can use the equation ΔS = ΔS° + Rln(Q), where R is the ideal gas constant and Q is the reaction quotient. Since the pressure is 1 atm and the reaction is at equilibrium, Q = K, the equilibrium constant.
3. Calculate the equilibrium constant (K) at 310 K using the Gibbs free energy change (ΔG°) and the equation ΔG° = -RTln(K). The Gibbs free energy change can be calculated using the standard enthalpy and entropy changes of the reaction.
To provide a specific numerical answer, I would need the standard entropy change for the reaction, the standard enthalpy change for the reaction, and the equilibrium constant K at 310K.
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