Top topic this week
Back to FAQs
Related FAQs
Frequently Asked Question
Questions asked by users might not always be phrased in the clearest way.
What is the empirical formula of a compound that is 21.2% nitrogen, 8.1% hydrogen, 24.3% sulfur, and 48.4% oxygen by mass? recheck answer solve everything step by step cancelation to cancelation gen chem solve step by step cancelation to cancelation gen chem step by step ep pls hydrogen is 1.0008
Accepted Answer
Here's how to determine the empirical formula step-by-step:
1. Assume a 100g sample: This makes the percentages directly translate to grams. So, we have 21.2g N, 8.1g H, 24.3g S, and 48.4g O.
2. Convert grams to moles:
N: 21.2g / 14.01g/mol = 1.51 mol
H: 8.1g / 1.008g/mol = 8.03 mol
S: 24.3g / 32.06g/mol = 0.758 mol
O: 48.4g / 16.00g/mol = 3.02 mol
3. Divide by the smallest mole value: This gives us the mole ratio in the simplest whole-number form.
N: 1.51 mol / 0.758 mol = 2.00
H: 8.03 mol / 0.758 mol = 10.6
S: 0.758 mol / 0.758 mol = 1.00
O: 3.02 mol / 0.758 mol = 3.98
4. Round to the nearest whole number: This represents the subscripts in the empirical formula.
N: 2
H: 11
S: 1
O: 4
5. Write the empirical formula: N₂H₁₁SO₄
Articles you might like