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What is the final molarity of the solution that results from mixing 50 ml of 1.5 m Na2SO4 with 25 ml of 0.5 m Na2SO4?
Accepted Answer
The final molarity of the solution can be calculated using the formula: M1V1 + M2V2 = (M3)(V3), where M1 is the molarity of the first solution, V1 is the volume of the first solution, M2 is the molarity of the second solution, V2 is the volume of the second solution, M3 is the molarity of the final solution, and V3 is the volume of the final solution. Plugging in the values, we get: (1.5 M)(50 mL) + (0.5 M)(25 mL) = (M3)(75 mL). Solving for M3, we get: M3 = 1.0 M.
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