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The ground state free ion term symbol for Co in Co[ox]3 is ⁴F. Here's how to determine it:
1. Electronic Configuration: Cobalt (Co) has an atomic number of 27, so its electronic configuration is [Ar] 3d⁷ 4s². In the complex Co[ox]3, the oxidation state of cobalt is +3, so the electronic configuration becomes [Ar] 3d⁶.
2. Hund's Rules: We use Hund's rules to determine the ground state term symbol:
Rule 1: Maximize the total spin multiplicity (S). For 3d⁶, we have S = 2 (four unpaired electrons).
Rule 2: Maximize the total orbital angular momentum (L). For 3d⁶, L = 3 (since we can have maximum of L = 3, 2, 1, 0, -1, -2, -3 values for the six electrons in 3d orbitals).
Rule 3: For a subshell that is less than half-filled, the ground state term symbol is the one with the lowest value of J (J = L - S). In this case, J = 1.
3. Term Symbol: The term symbol is written as 2S+1LJ, where:
2S+1 = Spin Multiplicity (4 in this case)
L = Symbol for the total orbital angular momentum (F for L = 3)
J = Total angular momentum (1 in this case)
Therefore, the ground state free ion term symbol for Co in Co[ox]3 is ⁴F.