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What is the ground state term for a d7 complex

Accepted Answer

The ground state term for a d7 complex is 4F. Here's how to determine it:
1. Determine the number of unpaired electrons: A d7 complex has 7 electrons in the d orbitals. These electrons will fill the orbitals according to Hund's rule, resulting in 3 unpaired electrons.
2. Calculate the total spin angular momentum (S): With 3 unpaired electrons, S = (3/2)
hbar.
3. Calculate the total orbital angular momentum (L): The d orbitals have an angular momentum quantum number (l) of 2. To determine L, we sum the l values of the unpaired electrons, considering the maximum possible value for each. For a d7 complex, this gives L = 2 + 2 + 2 = 6. Since L=6 corresponds to the F term symbol.
4. Combine S and L to obtain the term symbol: The term symbol is written as 2S+1LJ, where J is the total angular momentum, calculated as J = |L - S| to |L + S|. In this case, J can range from 3/2 to 9/2. The lowest energy state is when J is minimized, so J = 3/2.
Therefore, the ground state term for a d7 complex is 4F3/2.


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