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What is the percent by mass of carbon in sucrose, C12H22O11? solve step by step cancelation to cancelation gen chem step by step ep pls hydrogen is 1.0008

Accepted Answer

To calculate the percent by mass of carbon in sucrose (C12H22O11), follow these steps:
1. Find the molar mass of sucrose:
- Carbon (C): 12.011 g/mol
12 atoms = 144.132 g/mol
- Hydrogen (H): 1.008 g/mol
22 atoms = 22.176 g/mol
- Oxygen (O): 15.999 g/mol
11 atoms = 175.989 g/mol
- Total molar mass of sucrose: 144.132 + 22.176 + 175.989 = 342.297 g/mol
2. Calculate the mass of carbon in one mole of sucrose:
- Mass of carbon = 144.132 g/mol
3. Divide the mass of carbon by the total molar mass of sucrose and multiply by 100%:
- Percent by mass of carbon = (144.132 g/mol / 342.297 g/mol)
100% = 42.11%

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