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What is the ph of 0.01mnaoh(aq)solution will be
Accepted Answer
The pH of a 0.01 M NaOH(aq) solution can be calculated using the following equation:
pH = -log[H+]
where [H+] is the molar concentration of hydrogen ions in the solution.
For a 0.01 M NaOH solution, the concentration of hydroxide ions ([OH-]) is 0.01 M. The pOH of the solution can be calculated using the following equation:
pOH = -log[OH-]
which is equal to -log(0.01) = 2.
The pH of the solution can then be calculated using the following equation:
pH + pOH = 14
so, pH = 14 - pOH = 14 - 2 = 12.
Therefore, the pH of a 0.01 M NaOH(aq) solution is 12.
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