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What theoretical magnetic moment would be used to calculate [co(ox)3]4-
Accepted Answer
To calculate the theoretical magnetic moment of [Co(ox)3]4-, we need to consider the electronic configuration of the cobalt ion in the complex. The oxalate ligand (ox) is a weak field ligand, which means it will not cause a large splitting of the d orbitals. Therefore, the cobalt ion in this complex will likely have a high-spin configuration. The cobalt ion has a +2 charge in this complex. Therefore, the electron configuration of Co(II) is 3d7. In a high-spin configuration, there are 3 unpaired electrons. Using the spin-only formula, the magnetic moment is calculated as: μ = √n(n+2) BM, where n is the number of unpaired electrons. Thus, the theoretical magnetic moment of [Co(ox)3]4- is √3(3+2) BM = √15 BM ≈ 3.87 BM.
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