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What will be the ph of 0.8m CH3SO3H? ka of CH3SO3H = -1.9
Accepted Answer
The pH of a 0.8M solution of CH3SO3H can be calculated using the following equation:
Ka = [H+][CH3SO3-]/[CH3SO3H]
where Ka is the acid dissociation constant, [H+] is the molar concentration of hydrogen ions, [CH3SO3-] is the molar concentration of CH3SO3- ions, and [CH3SO3H] is the molar concentration of CH3SO3H.
Substituting the given values into the equation:
-1.9 = [H+][CH3SO3-]/0.8
Assuming that x is the molar concentration of H+ ions, then the molar concentration of CH3SO3- ions is also x. Substituting these values into the equation:
-1.9 = x^2/0.8
Solving for x:
x = 0.0125 M
Now, we can calculate the pH of the solution using the following equation:
pH = -log[H+]
Substituting the value of x:
pH = -log(0.0125)
pH = 1.9
Therefore, the pH of a 0.8M solution of CH3SO3H is 1.9.
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