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Which reagent is the limiting reactant when 0.450 mol Al(OH)3 and 0.550 mol H2SO4 are allowed to react?
Accepted Answer
To determine the limiting reactant, we need to compare the mole ratio of the reactants to the stoichiometric ratio in the balanced chemical equation. The balanced reaction is:
2 Al(OH)3 + 3 H2SO4 → Al2(SO4)3 + 6 H2O
From the equation, we see that 2 moles of Al(OH)3 react with 3 moles of H2SO4. Let's calculate the moles of H2SO4 required to react completely with the given moles of Al(OH)3:
0.450 mol Al(OH)3
(3 mol H2SO4 / 2 mol Al(OH)3) = 0.675 mol H2SO4
Since we only have 0.550 mol H2SO4, it is the limiting reactant. The reaction will stop once all of the H2SO4 is consumed, leaving some Al(OH)3 unreacted.
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