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Which would have least intense peaks in uv vi's tih2o6 2+, vh2o6 2+ mnh2o6 2+, nih2o6 2+
Accepted Answer
The intensity of UV-Vis peaks is related to the d-d transitions in transition metal complexes. The intensity of these transitions is influenced by the ligand field strength and the symmetry of the complex. Among the given complexes, [Ti(H2O)6]2+ would have the least intense peaks in UV-Vis spectroscopy because Ti(II) has a d2 configuration. The d-d transitions in [Ti(H2O)6]2+ are Laporte-forbidden, meaning they are electronically forbidden due to symmetry considerations. The other complexes (V(II), Mn(II), and Ni(II)) have more than one d electron and their d-d transitions are not as strongly forbidden. Therefore, the intensity of the UV-Vis peaks would be weaker for [Ti(H2O)6]2+ compared to the other complexes.
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