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Write the expression for the equilibriumconstant Keq for the reaction below:rnrn1) N2(g) + 3h2(g) → 2nh3(g)rnrnusing the equilibrium constant expressions youdetermined in column 1, calculate the value of Keqwhen the following concentrations are present:[n*h_{3}] = 0.01m [n_{2}] = 0.02m [h2] =0.0200
Accepted Answer
The expression for the equilibrium constant Keq for the reaction below is:
1) N2(g) + 3H2(g) → 2NH3(g)
Keq = [NH3]^2 / [N2] * [H2]^3
Using the equilibrium constant expressions you determined in column 1, calculate the value of Keq when the following concentrations are present:
[NH3] = 0.01M
[N2] = 0.02M
[H2] = 0.0200
Keq = (0.01)^2 / (0.02) * (0.02)^3
Keq = 0.0025/ 0.000016
Keq = 156.25
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