Top topic this week
Back to FAQs
Related FAQs
Frequently Asked Question
Questions asked by users might not always be phrased in the clearest way.
A refrigerant in an air-conditioning unit has a volume of 0.25 l. The unit is kept running in a room where the pressure is about 585 mm ofrnmercury (mm Hg). Assuming that the temperature inside the room remains constant, what will be the final pressure of the refrigerant when its volume is increased to 1.00 l?
Accepted Answer
Using the combined gas law, we can calculate the final pressure of the refrigerant:
PV = nRT
where P is pressure, V is volume, n is the number of moles, R is the ideal gas constant (0.0821 L*atm/(mol*K)), and T is temperature. Assuming that the temperature and number of moles of the refrigerant remain constant, we can write:
P1V1 = P2V2Plugging in the given values:
(585 mm Hg)(0.25 L) = P2(1.00 L)P2 = 146.25 mm HgTherefore, the final pressure of the refrigerant will be 146.25 mm Hg.
Articles you might like