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A refrigerant in an air-conditioning unit has a volume of 0.25 l. The unit is kept running in a room where the pressure is about 585 mm ofrnmercury (mm Hg). What will be the final pressure of the refrigerant when its volume is increased to 1.00 l?
Accepted Answer
Using Boyle's Law, which states that P₁V₁ = P₂V₂, we can calculate the final pressure (P₂) of the refrigerant. Given that the initial volume (V₁) is 0.25 L, the initial pressure (P₁) is 585 mmHg, and the final volume (V₂) is 1.00 L, we have:
P₁V₁ = P₂V₂
585 mmHg * 0.25 L = P₂ * 1.00 L
P₂ = (585 mmHg * 0.25 L) / 1.00 L
P₂ = 146.25 mmHg
Therefore, the final pressure of the refrigerant when its volume is increased to 1.00 L will be 146.25 mmHg.
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