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A student adds 4.8 g of magnesium to excess dilute hydrochloric acid. what mass of magnesium chloride would be made? ( mg = 24 , cl = 35.5 )

Accepted Answer

Here's how to solve this problem:
1. Write the balanced chemical equation:
Mg(s) + 2HCl(aq) → MgCl₂(aq) + H₂(g)
2. Calculate the moles of magnesium:
moles of Mg = mass / molar mass = 4.8 g / 24 g/mol = 0.2 mol
3. Determine the moles of magnesium chloride produced:
From the balanced equation, 1 mole of Mg reacts to produce 1 mole of MgCl₂.
Therefore, 0.2 mol of Mg will produce 0.2 mol of MgCl₂.
4. Calculate the mass of magnesium chloride:
mass of MgCl₂ = moles × molar mass = 0.2 mol × (24 g/mol + 2 × 35.5 g/mol) = 19 g
Therefore, 19 g of magnesium chloride would be made.


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