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Acid is a solution containing 4.90g of Nacid H2dmcube of solution.base is a solution containing 3.90g of sodium hydroxide dm cube of the solution.when Acid was titrated with base 25cm cube of base neutralized 24.5cm of acid calculate the molar concentration of Acid
Accepted Answer
Here's how to calculate the molar concentration of the acid:
1. Calculate moles of NaOH:
- Molar mass of NaOH = 40 g/mol
- Moles of NaOH = (3.90 g / 40 g/mol) = 0.0975 mol/dm³
2. Calculate moles of NaOH used:
- Volume of NaOH used = 25 cm³ = 0.025 dm³
- Moles of NaOH used = (0.0975 mol/dm³)
(0.025 dm³) = 0.0024375 mol
3. Determine the moles of acid neutralized:
- The reaction between the acid and NaOH is a 1:1 stoichiometry, meaning 1 mole of NaOH neutralizes 1 mole of the acid.
- Therefore, 0.0024375 moles of acid were neutralized.
4. Calculate the molar concentration of the acid:
- Volume of acid used = 24.5 cm³ = 0.0245 dm³
- Molar concentration of acid = (0.0024375 mol) / (0.0245 dm³) = 0.0995 mol/dm³
Therefore, the molar concentration of the acid is 0.0995 mol/dm³.
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