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Acid is a solution containing 4.90g of Nacid H2dmcube of solution.base is a solution containing 3.90g of sodium hydroxide dm cube of the solution.when Acid was titrated with base 25cm cube of base neutralized 24.5cm of acid calculate the molar mass of H2x
Accepted Answer
Here's how to calculate the molar mass of H₂X:
1. Calculate the moles of NaOH used:
- Convert the volume of NaOH solution from cm³ to dm³: 25 cm³ = 0.025 dm³
- Moles of NaOH = (concentration of NaOH)
(volume of NaOH) = (3.90 g/dm³)
(0.025 dm³) = 0.0975 g
- Convert mass of NaOH to moles: moles of NaOH = (0.0975 g) / (40.00 g/mol) = 0.00244 mol
2. Determine the moles of H₂X neutralized:
- From the balanced chemical equation, 1 mole of H₂X reacts with 2 moles of NaOH. Therefore, moles of H₂X = (0.00244 mol NaOH) / 2 = 0.00122 mol
3. Calculate the molar mass of H₂X:
- Convert the volume of H₂X solution from cm³ to dm³: 24.5 cm³ = 0.0245 dm³
- Molar mass of H₂X = (mass of H₂X) / (moles of H₂X) = (4.90 g) / (0.00122 mol) = 4016 g/mol
Therefore, the molar mass of H₂X is approximately 4016 g/mol.
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