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Calculate molarity of 0.2074 g of calcium hydroxide, Ca(OH)2, in 40.00 ml of solution
Accepted Answer
Calculate the molarity of 0.2074 g of calcium hydroxide, Ca(OH)2, in 40.00 mL of solution.
Given:
- Mass of Ca(OH)2: 0.2074 g
- Volume of solution: 40.00 mL = 0.04000 L
Steps:
1. Convert the mass of Ca(OH)2 to moles using its molar mass (74.09 g/mol):
0.2074 g Ca(OH)2 * (1 mol Ca(OH)2 / 74.09 g Ca(OH)2) = 0.002799 mol Ca(OH)2
2. Calculate the molarity (M) of the solution:
M = moles of solute / volume of solution in liters
M = 0.002799 mol / 0.04000 L = 0.0700 M
Therefore, the molarity of the calcium hydroxide solution is 0.0700 M.
Given:
- Mass of Ca(OH)2: 0.2074 g
- Volume of solution: 40.00 mL = 0.04000 L
Steps:
1. Convert the mass of Ca(OH)2 to moles using its molar mass (74.09 g/mol):
0.2074 g Ca(OH)2 * (1 mol Ca(OH)2 / 74.09 g Ca(OH)2) = 0.002799 mol Ca(OH)2
2. Calculate the molarity (M) of the solution:
M = moles of solute / volume of solution in liters
M = 0.002799 mol / 0.04000 L = 0.0700 M
Therefore, the molarity of the calcium hydroxide solution is 0.0700 M.
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