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Calculate molarity of one litre of 93% H2so4 solution(weight by volume) the density of solution is 1.85 gm per ml

Accepted Answer

Here's how to calculate the molarity of the H2SO4 solution:
1. Calculate the mass of H2SO4:
- 93% (w/v) means 93 g of H2SO4 are present in 100 mL of solution.
- For 1 L (1000 mL) solution, the mass of H2SO4 is (93 g / 100 mL)
1000 mL = 930 g
2. Calculate the moles of H2SO4:
- Molar mass of H2SO4 = (2
1.01) + 32.07 + (4
16.00) = 98.08 g/mol
- Moles of H2SO4 = 930 g / 98.08 g/mol = 9.48 mol
3. Calculate the molarity:
- Molarity (M) = moles of solute / volume of solution in liters
- Molarity = 9.48 mol / 1 L = 9.48 M
Therefore, the molarity of the 93% (w/v) H2SO4 solution is 9.48 M.

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