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Determine the Molarity of 1.75 moles sodium hydroxide solution with a density of 1.040 g/ml
Accepted Answer
Here is the molarity of 1.75 moles of sodium hydroxide solution with a density of 1.040 g/mL:
Calculation:
First, calculate the mass of the solution using its density and the volume of the solution that contains 1.75 moles of NaOH:
mass of solution = 1.75 moles NaOH * (40.00 g NaOH/ 1 mole NaOH) = 70 g NaOH
Next, using the mass of the solution and its density, calculate the volume of the solution:
volume of solution = 70 g NaOH * (1 mL/1.040 g) = 67.3 mL
Finally, calculate the molarity of the solution using its volume in liters and the number of moles of NaOH:
molarity = 1.75 moles NaOH / (67.3 mL * 1 L/1000 mL) = 26.0 M
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