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Determine the percent purity of acetic acid if the analyst uses 0.983 ml of the sample with an addition of 2 gtts of phenolphthalein. upon titration, it consumed 0.58 ml of 1.1514 n NaOH to reach pink color
Accepted Answer
The percent purity of acetic acid can be determined using the following formula:
Percent Purity = (Volume of NaOH used (mL) * Normality of NaOH (N) * Equivalent weight of Acetic acid (60.05 g/eq)) / (Volume of sample used (mL) * Density of Acetic acid (1.05 g/mL))
Plugging in the given values, we get:
Percent Purity = (0.58 mL * 1.1514 N * 60.05 g/eq) / (0.983 mL * 1.05 g/mL) * 100%
Percent Purity = 99.78%
Therefore, the percent purity of the acetic acid is 99.78%.
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