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For the reaction represented by the equation 2fe + o2 → 2feo, how many grams of iron(ii) oxide are produced from 8.00 mol of oxygen gas?

Accepted Answer

Here's how to solve the problem:
1. Balance the equation: The equation is already balanced: 2Fe + O2 → 2FeO
2. Convert moles of oxygen to moles of iron(II) oxide: The balanced equation shows that 1 mole of O2 produces 2 moles of FeO. Therefore, 8.00 moles of O2 will produce 8.00 moles
2 = 16.0 moles of FeO.
3. Convert moles of iron(II) oxide to grams: The molar mass of FeO is 55.845 g/mol (Fe) + 15.999 g/mol (O) = 71.844 g/mol.
16.0 moles FeO
71.844 g/mol = 1149.5 g FeO
Therefore, 1149.5 grams of iron(II) oxide are produced from 8.00 moles of oxygen gas.

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