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For the reaction represented by the equation Cl2 + 2kbr → 2kcl + Br2, how many grams of potassium chloride can be produced from 200 g each of chlorine gas and potassium bromide?
Accepted Answer
To determine the grams of potassium chloride (KCl) produced, we need to perform stoichiometric calculations. Here's how:
1. Balance the Equation: The equation is already balanced.
2. Convert Grams to Moles:
- Moles of Cl2 = (200 g Cl2) / (70.9 g/mol Cl2) = 2.82 mol Cl2
- Moles of KBr = (200 g KBr) / (119 g/mol KBr) = 1.68 mol KBr
3. Identify the Limiting Reactant: The limiting reactant is KBr because it produces less moles of KCl (1.68 mol KBr
(2 mol KCl / 2 mol KBr) = 1.68 mol KCl) compared to Cl2 (2.82 mol Cl2
(2 mol KCl / 1 mol Cl2) = 5.64 mol KCl).
4. Calculate Grams of KCl:
- Grams of KCl = (1.68 mol KCl)
(74.55 g/mol KCl) = 125 g KCl
Therefore, 125 grams of potassium chloride can be produced.
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