Top topic this week
Back to FAQs
Related FAQs
Frequently Asked Question
Questions asked by users might not always be phrased in the clearest way.
Given the following reaction and thermodynamic data, calculate the enthalpy of reaction (∆h°rxn).rnmncl2 + 2hno3 → Mn(NO3)2 + 2hclrnrncompound ∆hf° (kj/mol)rnmncl2 -555rnhno3 -207rnmn(no3)2 -1258rnhcl -167
Accepted Answer
The enthalpy of reaction (∆H°rxn) can be calculated using the following equation:
∆H°rxn = Σ∆Hf°(products) - Σ∆Hf°(reactants)
Plugging in the given values:
∆H°rxn = [(-1258) + 2(-167)] - [(-555) + 2(-207)]
∆H°rxn = -1634 - (-971)
∆H°rxn = -663 kJ/mol
Therefore, the enthalpy of reaction for the given reaction is -663 kJ/mol.
Articles you might like