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How many grams of Al2 o3 can be produced from 22 grams of Al?rnrn 4 al + 3 o2 --> 2 Al2O3
Accepted Answer
We can use stoichiometry to determine the mass of Al2O3 that can be produced from 22 grams of Al using the provided balanced chemical equation.
The molar mass of Al is 26.98 g/mol, and the molar mass of Al2O3 is 101.96 g/mol.
Using the mole ratio from the balanced equation, we can calculate the number of moles of Al2O3 that can be produced from 22 grams of Al:
22 g Al * (1 mol Al / 26.98 g Al) * (2 mol Al2O3 / 4 mol Al) = 0.3974 mol Al2O3
Now, we can convert the number of moles of Al2O3 to grams using its molar mass:
0.3974 mol Al2O3 * (101.96 g Al2O3 / 1 mol Al2O3) = 40.57 g Al2O3
Therefore, 22 grams of Al can produce 40.57 grams of Al2O3.
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